1 Introduction
In recent years, the study of frustrated spin model has become very active on two-dimensional (2D) square lattice with nearest-neighbor (NN) and next-nearest-neighbor (NNN) antiferromagnetic exchange interactions (known as
J1–
J2 model) [
1-
12]. The frustration is caused by the mutual competition between
J1 and
J2, which can trigger a rich phase diagram [
1]. Therefore, in the past, this model had been widely investigated by means of various theoretical methods (see, e.g., [
12], and references). It was well known that the ground state usually showed two possible antiferromagnetic states. One is called Néel state (NS), and the other is called stripe state (SS). The NS was characterized by an antiparallel alignment of NN spins with a corresponding magnetic wave vector
, see Fig. 1. The SS was twofold degenerated and the corresponding magnetic wave vectors were
and
, which were characterized by the fact that the NN spins take a parallel orientation in the vertical (horizontal) direction and an antiparallel orientation in the horizontal (vertical) direction, respectively, see Fig. 1. Investigations indicated that the system was an NS for
, and for
it turned to be an SS. When
, it was a nonmagnetic quantum phase [
1-
12]. At zero temperature, the key question is to understand the nature of the non-magnetic phase in the intermediate
regime [
3,
13].
For finite temperature, there is no long-range order for isotropic 2D model [
14]. Usually, an anisotropy is considered. This is because that an anisotropy, no matter how is faint, will cause a long-range order at finite temperature. Therefore, at finite temperature, the investigative emphasis is to discuss the effect of the anisotropy on the phase diagram. For example, Viana
et al. studied the phase diagram of a exchange anisotropic
J1–
J2 model at finite temperature [
2]. Their results indicated that between the paramagnetic and stripe phases the system underwent a first-order transition at low temperature and a second-order transition at high temperature. The investigation of Roscilde
et al. showed that when an Ising type exchange anisotropy was induced, there would be Chandra–Coleman–Larkin transition and Berezinskii–Kosterlitz–Thouless transition [
9]. These investigations indicated that the anisotropy played an important role.
A generalization of the
J1–
J2 Heisenberg antiferromagnetic model on a square lattice was introduced by Nersesyan and Tsvelik [
15], the so-called
J1a–
J1b–
J2 model [
16,
17]. It possesses more degrees of freedom to tune the fluctuation of system compared to the
J1–
J2 model, since the NN exchange interactions
and
along the
x and
y directions in this model are of different strengths. This feature leads naturally to an increased sensitivity of the underlying Hamiltonian to the presence of small perturbations.
Extensive band structure calculations for the vanadium phosphate compounds Pb
2VO(PO
4)
2, SrZnVO(PO
4)
2, BaZnVO(PO
4)
2, BaCdVO(PO
4)
2 had shown four different exchange couplings:
and
between the NN and
J2 and
between NNN [
18]. For example,
and
were obtained for SrZnVO(PO
4)
2. A possible candidate for
J1a–
J1b–
J2 model might be the compound (NO)Cu(NO
3)
3 though band-structure calculations showed a uniform spin chain model with different types of anisotropy and weak interchain couplings [
19,
20].
Our primary purpose of this work is to study the phase transition of the J1a–J1b–J2 model at finite temperature by using the double-time Green’s function (DTGF) method. Our results indicate that at (where η is the anisotropic parameter.) both NS and SS can exist and have the same critical temperature as long as . When , these two states may also exist, but their critical temperatures differ. The calculated free energies for these two cases show that a first-order phase transformation between NS and SS below critical points can occur. Which of the states is more stable, it will depend on the spatiality and exchange anisotropies of the system.
This paper is organized as follows. In Section 2, we introduce the theoretical model, and present the formulism of Green’s function to derive the self-consistent equation for evaluation of magnetizations. In Section 3, the numerical results are presented and discussed. Section 4 is our concluding remarks.
2 Model and method
The Hamiltonian of J1a–J1b–J2 model can be written as
where , and represent the three components of the spin-S operator for a spin at site i. The sums and run over the NN and NNN lattice sites, respectively. η denotes the anisotropic parameter with . Spin quantum number is and the lattice is the 2D square lattice. We fix and change other parameters in computation.
For the sake of convenience, we let Boltzmann constant . The sublattice magnetization is defined as . where is the assembly statistical average of spin operator Sz.
In this paper, we will use the DTGF method to investigate the phase transition properties of the system. The DTGF method used in Refs. [
21] and [
22] is known as the standard method in the study of magnetic systems. In this method one obtains a nonlinear differential equation in which the higher-order Green’s functions are coupled with the lower-order ones. Each of the higher-order Green’s functions is again written down in the form of a nonlinear equation and so on. To obtain tractable solutions, decoupling procedures have been invoked to terminate the hierarchy of Green’s functions generated by the equations of motion. Many results for the thermodynamic properties have been obtained in a frame of the simplest decoupling, i.e., the random phase approximation decoupling [
21,
22]. The decoupling provides a simple enough way for giving results in good agreement with other approaches and experiments in a wide range of temperatures and magnetic fields [
23,
24].
The Green’s function (GF) is defined as [
21,
22]
Here,
u is a parameter [
22]. After solving the GF by means of the method of equations of motion,
u will be ultimately set as zero to give the expression of magnetization [
22]. We derive the equation of motion of the GF by a standard procedure [
21,
22]. In the course of derivation, the higher order GFs have to be decoupled. In this paper, we apply random phase approximation [
21,
22] to decouple the higher order GFs in the equations of motion,
After decoupling of the higher order GFs and standard procedure [
21,
22], we obtain
where the summation of wave vector k runs over the first Brillouin zone. N is the number of lattice sites and
For , . Using Eqs. (4) and (5), we obtain
Here for the NS,
and for the SS,
Using Eqs. (5), (6) and the relation
, the sublattice magnetization is expressed by following formula [
21,
22]
The Néel points of the two configurations are expressed by
and
respectively.
3 Results and discussion
At zero temperature, our numerical calculations show that the phase diagram of the system is a classical result based on the DTGF. This case will not be discussed here. In this paper, we focus on the properties at finite temperature. Therefore, when we say zero temperature, we actually mean that temperature is very close to zero, which is denoted by .
3.1 Magnetic properties
In this section, the basic magnetic properties of the system under various parameters are presented and discussed.
Figure 2 plots the results of magnetization m as a function of temperature T at different parameter values. Figure 2(a) shows the case of and . It is seen that it is NS configuration at . For , it is SS configuration. As , it is an ordinary 2D antiferromagnetic model. There is no competition to cause frustration. As J2 increases from zero, the competition between and emerges. Since we have fixed in computation, this competition is actually between and J2. When the value of is fixed, the frustration becomes stronger with the increase of J2 value. This leads to that and decrease with the increase of J2. At , the frustration reaches maximum. Therefore, as J2 rises from 0.4, the role of J2 becomes more important and the frustration becomes comparatively weaker. It leads to that and increase with increasing J2 value.
Figure 2(a) indicates that the NS and SS have the same order-disorder transition point at . It reflects that both configurations can coexist. Since the value of J2 is exactly equal to , it is necessary to see whether at this conclusion is true for any other η and values. We change values and fix at , and the results are shown in Fig. 2(b). It is seen that, as takes value from 0.1 to 1, the critical temperatures of the two states are always equal. It indicates that this conclusion holds for different values at . As and , both NS and SS recover an ordinary one-dimensional anisotropic Heisenberg antiferromagnetic model. In this case, only plays a role. When increases from 0, under the condition of , the role of will gradually become weaker, see Fig. 2(b). However, for , numerical results indicate that the magnetization curves of the two states are the same, see Fig. 2(c). It reflects that the role of is predominant for small values.
In Fig. 3, is fixed and the η varies. It is seen that the two states have the same critical temperature at as long as , see Fig. 3(a). The magnetization curves of NS and SS are the same at , see Fig. 3(b). This is because that both NS and SS recover an ordinary two-dimensional Ising model. In this case, there are longitudinal but no transverse magnetic correlations between spins. Therefore, as , the sublattice magnetization becomes fully saturated, i.e., . Figure 3(a) demonstrates two features as the η value decreases from large to small. One is that both and increase until full saturation. The other is that the relative difference between and decreases. Both features are ascribed to the weaker transverse quantum fluctuation for stronger anisotropy. In combination of Figs. 2(b) and 3(a), it is drawn that at the two states always have the same critical temperature as long as .
Figure 4 plots the critical temperature as a function of J2 at different parameters. When and , as mentioned above, both NS and SS recover an ordinary one-dimensional exchange anisotropic Heisenberg antiferromagnetic model. As a consequence, they have the same critical temperature. For NS, as increases from 0, the competition between and J2 becomes weaker, the frustration of the system also becomes weaker, which leads to rise of the . SS is just a contrary case, i.e., the decreases with increasing . Due to these two reasons, the cross point of the critical temperature curves of the two states shifts rightwards with increasing , see Fig. 4(a). This is actually caused by the competition between and J2.
Figure 4(b) presents the enlargement of Fig. 4(a) when J2 is in the vicinity of 0.4 for . In this panel, the two lines divide the figure into four regions. The upper region, marked by “P”, means that the system is in paramagnetic state. The left and right regions are that the system is in NS and SS configurations, respectively. The lower region can be the coexistence of NS and SS.
Figure 4(c) plots the critical temperature as a function of J2 for different η values when . It is seen that the critical temperature increases with the decrease of η. The reason is that the anisotropy suppresses the fluctuation of the system. It leads to that the critical temperature rises. Therefore, the slopes of the critical temperatures of the two states become slower and slower with increasing η, see Fig. 4(c). It leads to the drop of the cross point of the critical temperature between NS and SS. Accordingly, the temperature corresponding to the cross point decreases with the increase of η. As the η value is close to 1, the crossing area disappears. One obtains from Fig. 4 that at and the two states always have the same critical temperature as long as .
We have known from the discussion above that both configurations can coexist at and when . One may ask which one is more stable. In the following, we manage to answer this question. The two configurations are different from each other, and so are their entropies at a fixed temperature. Therefore, the internal energy cannot be used to determine which one is more stable at each temperature. Under the same volume and temperature, the state with lower free energy is more stable.
The free energy can be evaluated numerically by means of the internal energy via
, where
represents the internal energy of the system, which is defined as the thermostatistical average of Hamiltonian,
[
22]. Computing internal energy involves the calculation of the transverse (
) and longitudinal (
) correlation functions. We do not present the lengthy derivation here. Please refer to Ref. [
25].
3.2 Possible phase transition at
In this section, the free energies of NS and SS at are presented at various parameters, respectively. Since the critical temperatures of the two states equal at , their critical temperatures are uniformly described by TN.
Figure 5 plots the internal energy and free energy as a function of temperature for different values when . The increases with temperature as it should be. The decreases monotonically with temperature. As increases from 0.001 to 0.038, the curves of NS and SS are identical, i.e., the difference between their free energies is negligible, see Figs. 5(a) and (b). It means that the system can be either the NS or SS, or coexistence of them. For convenience, we denote . As increases from , the free energy curves of the two states begin to separate, and , see Fig. 5(c). In this case, NS is more stable in the range of . Meanwhile, the free energy of SS with increasing temperature drops faster than of NS. Therefore, when further increases, the free energy curves of the two states cross at an intermediate temperature point, see Fig. 5(d). Therefore, below the temperature of this cross point, . It means that NS is more stable. Above the temperature of this cross point, , so that SS is more stable. At this cross point, there can occur a NS–SS phase transition. Note that, at the cross point, although the free energies of the NS and SS are the same, their internal energies differ, see Fig. 5(d). Subsequently, the specific heat at this cross point is discontinuous (not shown). Therefore, it is a first-order transition.
Figure 6 plots and as a function of temperature for different η values when . Similar to Fig. 5(b), for a fixed , there is an upper limit . When , the difference of the free energy between NS and SS is negligible, i.e., , see Figs. 6(a) and (b). When η increases from , , see Fig. 6(c). As η continues increasing, the free energy curves of the two states cross, see Fig. 6(d). Therefore, its results are similar to Fig. 5. However, it can be found from Figs. 5(d) and 6(d) that, when the values of η and/or increase, it can lead to that the free energy curves of SS with increasing temperature drops faster than of NS. Therefore, when η and/or takes a certain value, the value may be greater than . To be explicit, Fig. 7 presents free energy as a function of temperature for when , 0.999. It is seen that the free energy curves of SS with increasing η drops faster than of NS. When , , see Fig. 7(b). In this case, it means that SS is more stable.
In Figs. 5–7, we only calculate the free energies of the NS and SS as a function of temperature at fixed and η when , one may expect to obtain a number of transitions between NS and SS. Therefore, in Fig. 8, we present a comprehensive recognition of the effect of parameters and η on the free energies of the two states below the . All possible relationships are presented in Fig. 8(a). There are four regions in Fig. 8(a). Some of them are very narrow. Then we show a enlargement of the region in Fig. 8(b).
In region I, the difference of the free energy between the two states is negligible. So it is denoted as . The examples are the curves in Figs. 5(a, b) and Figs. 6(a, b). It indicates that in this region the system may be either the NS or SS, or coexistence of them.
In region II, the free energy of NS is always less than SS. The examples are the curves in Fig. 5(c) and Fig. 6(c). This region is denoted as . It shows that in region II NS is more stable.
In region III, the curves of the two states cross. The examples are curves in Figs. 5(d), 6(d), and 7(a). When the temperature closes to zero, . However, when the temperature approaches to the TN, . Therefore, as temperature is near zero, the state of the system should be NS, and as temperature rises, it is possible to occur a first-order phase transformation from the NS to SS at the cross point below the .
In region IV, the free energy of is always larger than . It shows that in region IV SS is more stable. The example is the curves in Fig. 7(b).
In Fig. 8, two points need to be stressed. One is that in region I, the free energies of NS and SS are very close to each other and one cannot tell which one is more stable. However, as
increases from
, region I gradually transits to region II. The other is that for region IV, its boundary seems to be
. This is because we only compute the case of
, see Fig. 8(b). Actually, its boundary is
. For
, the system is a two-dimensional isotropic antiferromagnetic model. According to the well-known Mermin–Wagner theorem [
14], there is no long-range order at finite temperature for 2D isotropic antiferromagnetic system. Therefore, this case shall be not discussed at finite temperature.
3.3 Possible phase transition at
When the J2 value is apart from , the NS and SS can also coexist, as revealed by Fig. 4(b). In this case, the system should also be in the state with the lower free energy at any temperature. If the curves of the NS and SS have cross point, there may occur a phase transition between them. Figure 9 plots the free energy as a function of temperature for different J2 values when and . It is seen from Figs. 9(a) and (b) that, as the value of J2 increases from 0.25 to 0.39, the difference of the free energies between the two states gradually becomes small, especially near critical temperature, see the curves in Fig. 9(b). It seems to tell us when J2 approaches 0.4, the free energy curves of the two states may cross. Nevertheless, numerical calculations indicate that at , . This case is not shown here. In fact, Fig. 8(a) clearly shows at and . Therefore, is always less than at . This means that in this case NS is more stable. For the case of , one should distinguish three cases. (1) , is still less than , see the curves with in Fig. 9(c). In this case, NS is more stable. At , when , the free energies of the two states is negligible, i.e., . (2) When , the free energy curves of the two states cross. The examples are the curves with in Fig. 9(c). At cross point, a first-order phase transformation between NS and SS may occur. Below the cross point, SS is more stable. Above the cross point, NS is more stable. (3) When , is always greater than . The examples are the curves in Fig. 8(d). In this case, SS is more stable. Fig. 8 reflects a fact that, as the value of J2 increases, the value of is rising, while is decreasing. So on the whole, the curve of is rising, and is down.
Let us make a summary of our results for the case of .
(i) The higher the critical temperature, the lower the , and the larger the difference between the critical temperature of NS and SS, the larger the difference between and .
(ii) For , is always less than , i.e., in this case, NS is always more stable.
(iii) When , one should distinguish three cases. (a) When , is still less than . (b) When , becomes greater than , and the free energy curves of the two states have a cross point, at which a first-order phase transformation between NS and SS may occur. (c) When , is always greater than . The and values depend on the values of η and .
4 Concluding remarks
In this paper, a possible phase transition of the 2D frustrated anisotropic J1a–J1b–J2 Heisenberg antiferroamgnetic model with spin-1/2 has been studied by means of the double-time Green’s function method. Our results have shown that under the condition of the NS and SS have the same critical temperature as long as . For the case of , our results indicate that these two states can also exist, while they have different critical temperatures. Thus a possible phase transformation between NS and SS with the case of and has been also discussed, respectively.
In order to discuss explicitly which state is more stable, free energy as a function of temperature is calculated.
When , our results show that the effect of and η on the free energies of the NS and SS may be divided into four regions, see Fig. 8. In region I, the difference between the free energies of the NS and SS is negligible, i.e., . In this case, the system can be in either the NS or SS, a coexistence of them. In region II, , NS is more stable. In region III, a first-order phase transition between NS and SS can occur at a temperature. Below temperature of the cross point, NS is more stable. Above temperature of the cross point, SS is more stable. For region IV, , SS is more stable.
For the case of , when , the NS is always more stable than the SS below . But for , there are three cases. (i) When J2 takes value in the vicinity of , the NS is more stable. (ii) When the J2 value increases further, a first-order phase transformation between the two states may occur. Therefore, in this case, when the temperature approaches zero, the SS is more stable. Near , the NS is more stable. (iii) When the J2 value continues increasing, the SS is more stable.
Higher Education Press and Springer-Verlag GmbH Germany, part of Springer Nature 2019