Association schemes based on partial subspaces of type (2, 0, 1) in singular symplectic space

Zengti LI , Guanghui FENG

Front. Math. China ›› 2026, Vol. 21 ›› Issue (1) : 1 -13.

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Front. Math. China ›› 2026, Vol. 21 ›› Issue (1) :1 -13. DOI: 10.3868/s140-DDD-026-0001-x
RESEARCH ARTICLE
Association schemes based on partial subspaces of type (2, 0, 1) in singular symplectic space
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Abstract

Let Fq(2ν+l) be the (2ν+l)-dimensional singular symplectic space over the finite field Fq, K be a fixed maximal totally isotropic subspace in Fq(2ν+l), and Ω be the set of all subspaces of type (1,0,0) not contained in K. In this paper, we construct a class of association schemes by using all subspaces of type (2,0,1) that contain a subspace from Ω, and compute all intersection numbers of the constructed schemes.

Keywords

Association schemes / singular symplectic space / finite field

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Zengti LI, Guanghui FENG. Association schemes based on partial subspaces of type (2, 0, 1) in singular symplectic space. Front. Math. China, 2026, 21(1): 1-13 DOI:10.3868/s140-DDD-026-0001-x

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1 Introduction

It is assumed that Fq is a finite field with q elements, where q is a prime power. Let Fq(2ν+l) be the (2ν+l)-dimensional row vector space over the finite field Fq and

Kl=(0I(ν)I(ν)00(l)).

If all (2ν+l)×(2ν+l) matrices T over the finite field Fq satisfying TKlTT=Kl form a set, with matrix multiplication, there will be the singular symplectic group of degree 2ν+l over the finite field Fq, denoted by Sp2ν+l(Fq). The vector space Fq(2ν+l) under the right multiplication action of Sp2ν+l(Fq) is called the (2ν+l)-dimensional singular symplectic space over the finite field Fq.

Let P be an m-dimensional subspace in Fq(2ν+l) and E the subspace generated by ei(1i2ν+l) in Fq(2ν+l), where ei(1i2ν+l)is the row vector in Fq(2ν+l) whose ith component is 1 and the other components are 0. An m-dimensional subspace P in the (2ν+l)-dimensional singular symplectic space refers to a subspace of type (m,s,k) if the rank of PKlPT is 2s and dim(PE)=k. In particular, a subspace of type (ν,0,0) is called a maximal totally isotropic subspace. A subspace of type (m,s,k) exists if and only if 0kl and 2smkν+s.

Association schemes can be viewed as edge colorings of complete graphs satisfying good regularity conditions, which have been widely applied in coding theory, design theory, graph theory and group theory and further studied in many chapters of books or books [1-6].

Definition 0.1 [1] Let X be a set of cardinality n and Ri(i=0,1,,d) be subsets of X×X with the following properties:

(1) R0={(x,x)xX};

(2) X×X=R0R1Rd, and RiRj=, if ij;

(3) For i{0,1,,d}, there exists RiT=Ri, where RiT={(x,y)(y,x)Ri};

(4) For i,j,k{0,1,,d} and any (x,y)Rk, the number pijk=∣{ZX(x,z)Ri,(z,y)Rj} is a constant independent of the choice of (x,y) in Rk.

Such a configuration χ=(X,{Ri}0id) is called an association scheme on X with d classes.

Association schemes play an important role in algebraic combinatorics. Wan et al. [10, 11] computed all parameters of the bipartite scheme. As a generalized bipartite scheme, Rieck [9] constructed association schemes with the subspaces of a given dimension in finite classical polar spaces. Wei and Wang (see [15, 16]) gave suborbits under the action of finite classical groups on the set of m-dimensional totally isotropic subspaces. Guo et al. [7, 8] constructed association schemes with the maximal totally isotropic subspaces in singular classical spaces. As generalized Grassmann schemes and bilinear forms schemes, Wang et al. [12, 13] constructed association schemes on attenuated spaces and singular linear spaces. Wang et al. [14] constructed a class of association schemes with minimal flats in classical polar spaces. Gao et al. [5] constructed association schemes with subspaces of type (m,s,0) in singular symplectic space.

In this paper, let K0 be a fixed maximal totally isotropic subspace in the symplectic space Fq(2ν), K=(K0K1) be a fixed maximal totally isotropic subspace in the singular symplectic space Fq(2ν+l), and Ω be the set of all subspaces of type (1,0,0) in Fq(2ν+l) not contained in K. We construct a class of association schemes with subspaces of type (2,0,1) in Fq(2ν+l) that contain a subspace from Ω. The following shows the results.

Theorem 0.1  It is assumed that the characteristic of Fq is 2 and l2. Let X be the set of all subspaces of type (2,0,1) with matrix representation as follows:

2νl(u1u20u),

where (u1,u2)Ω. Assume t=0 or t=1. For any two elements in X,

P=(x1x20x),Q=(y1y20y),

and the relations on X are defined as follows:

(1) (P,Q)R(0,t), if x1=y1, dim(xy)=1t, and P+Q is a subspace of type (2+t,0,1+t);

(2) (P,Q)R(1,t), if x1=y1,dim(xy)=1t, and P+Q is a subspace of type (3+t,0,2+t);

(3) (P,Q)R(2,t), if x1+y1 is a subspace of type (2,1), dim((x1+y1)K0)=1,dim(xy)=1t, and P+Q is a subspace of type (3+t,1,1+t);

(4) (P,Q)R(3,t), if x1+y1 is a subspace of type (2,1), dim((x1+y1)K0)=0,dim(xy)=1t, and P+Q is a subspace of type (3+t,1,1+t);

(5) (P,Q)R(4,t), if x1+y1 is a subspace of type (2,0), dim((x1+y1)K0)=1,dim(xy)=1t, and P+Q is a subspace of type (3+t,0,1+t);

(6) (P,Q)R(5,t), if x1+y1 is a subspace of type (2,0), dim((x1+y1)K0)=0,dim(xy)=1t, and P+Q is a subspace of type (3+t,0,1+t).

Then a symmetric association scheme can be obtained. The parameters d,v, and n(r,t)(r=0,1,2,3,4,5,t=0,1) are determined by Lemma 1.1, and the intersection numbers p(i,j)(λ,μ)(r,t) are gained from Eqs. (6)‒(29) in Section 1.

2 Proof of Theorem 0.1

In this section, we prove Theorem 0.1 and compute all parameters of the obtained association schemes.

Let q be a prime power and m1,m2 be two integers. For simplicity, we use the Gaussian coefficient:

[m2m1]q=i=m2m1+1m2(qi1)i=1m1(qi1).

It is defined that when m1=m2, [m2m1]q=1; when m1<0 or m2<m1, [m2m1]q=0.

Proposition 1.1 [13]  For 1mn and 0imin{m,nm}, let P and Q be two fixed m-dimensional subspaces in Fq(n) such that dim(PQ)=mi. Then the number of m-dimensional subspaces S in Fq(n) satisfying dim(PS)=ms and dim(SQ)=mu is

psui(m,n)=ρ+α=u,β+γ=mu,ρ+γsqωk=i+ρs+1iγ(qk1)×[αsργ]q[iα]q[iγ]q[miβ]q[nmiρ]q,

where ω=12(sγρ)(sγρ1)+(mβ)(mβi)+ρ(2iαγ).

Let Fq(2ν) be the 2ν-dimensional vector space over the finite field Fq, W be a fixed maximal totally isotropic subspace in Fq(2ν), and Θ be the set of all 1-dimensional subspaces not contained in W.

Proposition 1.2 [14]  It is assumed that the characteristic of Fq is 2. A partition of Θ×Θ is defined as follows:

(1) R0={(P,P)PΘ},

(2) R1={(P,Q)P,QΘ,P+Q is non-isotropic and dim((P+Q)W)=1},

(3) R2={(P,Q)P,QΘ,P+Q is non-isotropic and dim((P+Q)W)=0},

(4) R3={(P,Q)P,QΘ,P+Q is totally isotropic and dim((P+Q)W)=1},

(5) R4={(P,Q)P,QΘ,P+Q is totally isotropic and dim((P+Q)W)=0}.

Then χ=(Θ,{Ri}i=04) is a symmetric association scheme with parameters:

{k1=(q1)qν1,k2=qν(qν11),k3=qν11,{p111=(q2)qν1,p131=qν11,p241=(qν11)qν1,{p232=(q1)qν21,p242=(qν2q+1)qν2,p333=qν12,p121=p231=p331=p332=0.

According to Proposition 1.2, the construction in Theorem 0.1 yields a symmetric association scheme.

In this section, assume

K=(ννlI(ν)00),Q=(eν+1e2ν+1).

Lemma 1.1  The parameters of the association schemes determined by Theorem 0.1 are

d=11,v=qν+l1(qν1)(ql1)(q1)2,

n(0,t)=qt[l1t]q,n(1,t)=q2t(qlt11)[l1t]q,n(2,t)=(q1)qν+l+t2[l1t]q,n(3,t)=qν+l+t1(qν11)[l1t]q,n(4,t)=ql+t1(qν11)[l1t]q,n(5,t)=qν+l+t1[ν11]q[l1t]q.

Proof According to the definition of R(i,j), the number of the class in the association scheme is

d=11.

Let V=(u1u20u) be an arbitrary element in X. The number of ways to choose the subspace u is ql1q1. Since the action of Sp2ν+l(Fq) on the set of subspaces in the same type is transitive, the number of V does not depend on the specific choice of u. Without losing generality and assuinge u=(10), V has a matrix representation

V=(u10u22010),

where u22 is an arbitrary 1×(l1) matrix. According to [12, Lemma 2.2], the number of u1 is qνqν1q1, and the number of V is qν+l1(qν1)(ql1)(q1)2. Therefore,

v=qν+l1(qν1)(ql1)(q1)2.

Next, we compute n(i,t)(0i5,0t1). We only compute n(2,t) in detailand the others can be calculated similarly.

n(2,0) is the number of subspaces P such that (Q,P)R(2,0). Assume

P=(x10x2010).

According to Proposition 1.2, the number of x1 is (q1)qν1. Then the number of P is ql1(q1)qν1=(q1)qν+l2. So

n(2,0)=(q1)qν+l2.

n(2,1) is the number of subspaces U such that (Q,U)R(2,1). Assume

U=(y1y20y).

According to Proposition 1.2, the number of y1 is (q1)qν1. The number of ways to choose the subspace y is [l1]q1. Then the number of P is (q1)qν1(ql1q11)ql1=(ql11)qν+l1. So

n(2,1)=(ql11)qν+l1.

According to Eqs. (3) and (4), there is

n(2,t)=(q1)qν+l+t2[l1t]q.

Next, we compute the intersection numbers. According to Proposition 1.1, there is

p(0,j)(0,ν)(0,t)=pjνt(1,l).

Assume

W=(e1+eν+1e2ν+1),

then (W,Q)R(2,0).

p(3,0)(5,0)(2,0) is the number of subspaces A such that (W,A)R(3,0) and (Q,A)R(5,0). Assume

A=(2ν1l1a10a2010).

According to Proposition 1.2, the number of a1 is (qν11)qν1. Then the number of A is ql1(qν11)qν1=(qν1 1)qν+l2. So

p(3,0)(5,0)(2,0)=(qν11)qν+l2.

p(3,1)(5,1)(2,0) is the number of subspace B such that (W,B)R(3,1) and (Q,B)R(5,1). Assume

B=(2νlb1b20b).

According to Proposition 1.2, the number of b1 is (qν11)qν1. The number of ways to choose the subspace b is [l1]q1. Therefore, the number of B is

ql1(qν11)qν1([l1]q1)=(qν11)(ql11)qν+l1q1.

Hence

p(3,1)(5,1)(2,0)=(qν11)(ql11)qν+l1q1.

It is known that p(3,0)(5,1)(2,0)=p(3,1)(5,0)(2,0)=0. So

p(3,j)(5,μ)(2,0)={(qν11)qν+l2,ifj=μ=0,0,ifjμ,(qν11)(ql11)qν+l1q1,ifj=μ=1.

Assume

H=(e1+eν+1e2ν+2),

then (Q,H)R(2,1)

p(3,0)(5,1)(2,1) is the number of subspace C such that (Q,C)R(3,0) and (H,C)R(5,1). Assume

C=(2ν1l1c10c2010).

According to Proposition 1.2, the number of c1 is (qν11)qν1. Therefore, the number of C is (qν11)qν1ql1=(qν11)qν+l2. So

p(3,0)(5,1)(2,1)=(qν11)qν+l2.

Similar to the calculation of p(3,0)(5,1)(2,1), we obtain

p(3,1)(5,0)(2,1)=(qν11)qν+l2.

p(3,1)(5,1)(2,1) is the number of subspace D such that (Q,D)R(3,1) and (H,D)R(5,1). Assume

D=(2νld1d20d).

According to Proposition 1.2, the number of d1 is (qν11)qν1. The number of ways to choose the subspace d is [l1]q2. Therefore, the number of D is

ql1(qν11)qν1([l1]q2)=(qν11)(ql2q+1)qν+l2q1.

And

p(3,1)(5,1)(2,1)=(qν11)(ql2q+1)qν+l2q1.

It is seen that

p(3,0)(5,0)(2,1)=0.

Therefore,

p(3,j)(5,μ)(2,1)={0,ifj=μ=0,(qν11)qν+l2,ifjμ,(qν11)(ql2q+1)qν+l2q1,ifj=μ=1.

There is

p(3,0)(5,0)(2,1)=p(3,0)(5,1)(2,0)=p(3,1)(5,0)(2,1)=0,

and

p(3,j)(5,μ)(2,t)={(qν11)(ql11)qν+l1q1,ift=0,j=μ=1,(qν11)qν+l2,ift=1,jμ,ort=j=μ=0,(qν11)(ql2q+1)qν+l2q1,ift=j=μ=1.

According to Proposition 1.2 and the calculations mentioned above, we obtain the following intersection numbers:

p(r,0)(λ,0)(i,1)=p(r,0)(λ,1)(i,0)=p(r,1)(λ,0)(i,0)=0(0i,r,λ5),

p(0,j)(1,μ)(0,t)={q1,ift=j=1,μ=0,ql2q+1,ift=j=μ=1,0,ift=μ=1,j=0,ort=0,

p(i,j)(i,μ)(0,t)={n(i,k),ift=0,j=μ=k,0k1,1i5,ql1q,ifi=1,t=1,jμ,(ql2q+1)(ql12q+1)q1,ifi=1,t=j=μ=1,(q1)qν+l2,ifi=2,t=1,jμ,(ql2q+1)qν+l2,ifi=2,t=j=μ=1,(qν11)qν+l1,ifi=3,t=1,jμ,(qν11)(ql2q+1)qν+l1q1,ifi=3,t=j=μ=1,(qν11)ql1,ifi=4,t=1,jμ,(qν11)(ql2q+1)ql1q1,ifi=4,t=j=μ=1,(qν11)qνl1q1,ifi=5,t=1,jμ,(qν11)(ql2q+1)qν+l1(q1)2,ifi=5,t=j=μ=1,

p(1,j)(1,μ)(1,t)={ql12,ift=j=μ=0,q2(ql21)(ql1q1)q1,ift=0,j=μ=1,ql1q1,ift=1,jμ,q(ql12q+1)+(qlq2q11)(ql12q),ift=j=μ=1,

p(2,j)(2,μ)(1,t)={(ql11)qν+l1,ift=0,j=μ=1,(q1)qν+l2,ift=1,jμ,ort=j=μ=0,(ql2q+1)qν+l2,ift=j=μ=1,

p(3,j)(3,μ)(1,t)={(ql11)(qν11)qν+lq1,ift=0,j=μ=1,(qν11)qν+l1,ift=1,jμ,ort=j=μ=0,(ql2q+1)(qν11)qν+l1q1,ift=j=μ=1,

p(4,j)(4,μ)(1,t)={(ql11)(qν11)qlq1,ift=0,j=μ=1,(qν11)ql1,ift=1,jμ,ort=j=μ=0,(ql2q+1)(qν11)ql1q1,ift=j=μ=1,

p(5,j)(5,μ)(1,t)={(ql11)(qν11)qν+l(q1)2,ift=0,j=μ=1,(qν11)qν+l1q1,ift=1,jμ,ort=j=μ=0,(ql2q+1)(qν11)qν+l1(q1)2,ift=j=μ=1,

p(2,j)(2,μ)(2,t)={(q2)(ql11)qν+l1q1,ift=0,j=μ=1,(q2)qν+l2,ift=1,jμ,ort=j=μ=0,(ql22q+1)(q2)qν+l2q1,ift=j=μ=1,

p(2,j)(4,μ)(2,t)={(qν11)(ql11)qlq1,ift=0,j=μ=1,(qν11)ql1,ift=1,jμ,ort=j=μ=0,(ql2q+1)(qν11)ql1q1,ift=j=μ=1,

p(3,j)(5,μ)(2,t)={(qν11)(ql11)qν+l1q1,ift=0,j=μ=1,(qν11)qν+l2,ift=1,jμ,ort=j=μ=0,(ql2q+1)(qν11)qν+l2q1,ift=j=μ=1,

p(3,j)(4,μ)(3,t)={(q1)(ql11)qν+l2q1(ql11)qlq1,ift=0,j=μ=1,(q1)qν+l3ql1,ift=1,jμ,ort=j=μ=0,(q1)(ql2q+1)qν+l3q1(ql2q+1)ql1q1,ift=j=μ=1,

p(3,j)(5,μ)(3,t)={(qν2q+1)(ql11)qν+l2q1,ift=0,j=μ=1,(qν2q+1)qν+l3,ift=1,jμ,ort=j=μ=0,(qν2q+1)(ql2q+1)qν+l3q1,ift=j=μ=1,

p(4,j)(4,μ)(4,t)={(qν12)(ql11)qlq1,ift=0,j=μ=1,(qν12)ql1,ift=1,jμ,ort=j=μ=0,(qν12)(ql2q+1)ql1q1,ift=j=μ=1,

p(5,j)(5,μ)(2,t)={(qν11)(ql11)qν+l1(q1)2,ift=0,j=μ=1,(qν11)qν+l2q1,ift=1,jμ,ort=j=μ=0,(ql2q+1)(qν11)qν+l2(q1)2,ift=j=μ=1,

p(3,j)(3,μ)(3,t)={(q1)(qν2q+1)(ql11)qν+l2q1,ift=0,j=μ=1,(q1)(qν2q+1)qν+l3,ift=1,jμ,ort=j=μ=0,(ql2q+1)(q1)(qν2q+1)qν+l3q1,ift=j=μ=1,

p(4,j)(5,μ)(3,t)={(ql11)qν+l2q1,ift=0,j=μ=1,qν+l3,ift=1,jμ,ort=j=μ=0,(ql2q+1)qν+l3q1,ift=j=μ=1,

p(5,j)(5,μ)(3,t)={(ql11)(qν2q+1)qν+l2(q1)2,ift=0,j=μ=1,(qν2q+1)qν+l3q1,ift=1,jμ,ort=j=μ=0,(ql2q+1)(qν2q+1)qν+l3(q1)2,ift=j=μ=1,

p(5,j)(5,μ)(4,t)={(ql11)(qν21)qν+l(q1)2,ift=0,j=μ=1,(qν21)qν+l1q1,ift=1,jμ,ort=j=μ=0,(ql2q+1)(qν21)qν+l1(q1)2,ift=j=μ=1,

p(5,j)(5,μ)(5,t)={(ql11)(qν2q+1)qν+l2(q1)2,ift=0,j=μ=1,(qν2q+1)qν+l3q1,ift=1,jμ,ort=j=μ=0,(ql2q+1)(qν2q+1)qν+l3(q1)2,ift=j=μ=1,

p(2,j)(3,μ)(2,t)=p(3,j)(4,μ)(2,t)=p(4,j)(4,μ)(2,t)=p(4,j)(4,μ)(3,t)=0,

p(2,j)(5,μ)(2,t)=p(4,j)(5,μ)(2,t)=p(4,j)(5,μ)(4,t)=0.

Since n(i,t)p(r,j)(λ,μ)(i,t)=n(r,j)p(i,t)(λ,μ)(r,j), all the remaining intersection numbers of this association scheme can be determined by Eqs. (6)‒(29), and Theorem 0.1 is proved.

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