Alternating link and its generalization

Liangxia WAN

Front. Math. China ›› 2023, Vol. 18 ›› Issue (1) : 1 -14.

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Front. Math. China ›› 2023, Vol. 18 ›› Issue (1) : 1 -14. DOI: 10.3868/S140-DDD-023-005-X
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Alternating link and its generalization

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Abstract

The alternating links give a classical class of links. They play an important role in Knot Theory. Ozsváth and Szabó introduced a quasi-alternating link which is a generalization of an alternating link. In this paper we review some results of alternating links and quasi-alternating links on the Jones polynomial and the Khovanov homology. Moreover, we introduce a long pass link. Several problems worthy of further study are provided.

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Alternating links / quasi-alternating links / pass replacement / Jones polynomial / Khovanov homology

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Liangxia WAN. Alternating link and its generalization. Front. Math. China, 2023, 18(1): 1-14 DOI:10.3868/S140-DDD-023-005-X

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1 Introduction

A knot is a piecewise linear simple closed curve without intersection in R3 (or S3). A link consists of such finite simple closed curves in R3 (or S3). Each curve is called a component of the link. In fact, a knot is a link with one component. If there is an orientation preserving piecewise linear homeomorphism h:S3S3 which preserves the orientation such that h(L1)=L2, then the link L1 is equivalent to the link L2. The unknot is the knot equivalent to a circle. How to distinguish nonequivalent links is an essential problem in Knot Theory. We need to find some invariants of links in order to distinguish the distinct links.

The history of knots can be traced back to the beginning of human being tying knots with ropes. Knot Theory, that is a mathematical study of knots, is probably recognized first by Gauss. He introduced the linking number in the 19th century [19]. Because of the mystery of the problem itself, it is widely concerned by many mathematicians in fields of Topology, Algebra, Geometry, Graph theory Combinatorics, etc. It is used to study related topics by biologists and physicists et al. [71, 55]. In this paper, we review some results on the Jones polynomial and the Khovanov homology of alternating links and quasi-alternating links. Moreover, a long pass link is introduced and several problems are given. The properties of other polynomial invariants can be referred to the review articles [13, 57].

2 Preliminaries

A link projection is obtained by projecting a link to the plane. If there are a finite number of double crossings in a projection and the over-crossing line and the under-crossing line transverse at each crossing in the plane, then the projection is called a diagram of the link. If the over and under crossing at a crossing are not considered, a 4-regular planar graph is obtained, which is called the shadow of the diagram. A path is an alternating sequence of vertices and edges. A graph is connected if there is a path for any two distinct vertices. A vertex u of a graph G is called a cut vertex if E(G) is the partition of E1 and E2 such that G[E1] and G[E2] have just the common vertex v. Here, G[Ei] is the subgraph of G whose vertex set is the set of vertices incident with an edge in Ei and whose edge set is Ei for i=1,2. A diagram is reduced if its shadow doesn't contain a cut vertex. Reidermeister and Alexander and Briggs independently introduced three Reidermeister moves (Fig.1) and obtained the following result in 1926 [63, 2]. Then a diagram is connected (or non-split) if it isn't equivalent to the disjoint union of two diagrams.

Theorem 1  If two diagrams differ by a finite sequence of Reidermeister moves, then they are equivalent.

Jones discovered the famous polynomial invariant−the Jones polynomial in 1984 [28], who won the Fields Prize for this work in 1990. Kauffman introduced the bracket polynomial and then gave a relatively simple expression of the Jones polynomial in 1987 [31]. Let D be a diagram of a link L. Each crossing can be resolved by using 0-revolution or 1-revolution (Fig.2). A state of D is obtained by resolving each crossing. Let SD be the collection of all states of D and let c(D) be the number of crossings in D. Obviously, D has 2c(D) states. Let b(α) and l(α) denote the number of 1-revolutions and loops in αSD, respectively. Then a(α) is the number of 0-revolutions in α where a(α)=c(α)b(α). Set pi(D)=αSD,l(α)=iAa(α)b(α). The bracket polynomial is as follows:

<D>=i1pi(D)(A2A2)i1.

Definition 1 [31, 72] Let D be a diagram of an oriented link L. Set ω(D) to be the writhe of D and set t=A4. Then the Jones polynomial of L is as follows:

VL(t)=(A)3ω(D)<D>.

The breadth is the difference between the maximal degree of t and the minimal degree t. Suppose that VL(t)=tri=0naiti for n,r0. If ai0 for each 0in, then VL(t) is gapless.

Khovanov proposed a cohomological invariant of a link – Khovanov homology [33], which is a categorification of the Jones polynomial. The Khovanov homology encodes more information about knots than the Jones polynomial. It detects the unknot, the trefoil knot and the figure-eight knot etc. [4, 5, 6, 9, 23, 35, 41, 42, 46, 81, 82]. Rasmussen defined a knot invariant s(K) on the Khovanov homology by using Lee’s spectral sequence [62]. s(K) provides a lower bound for the smooth slice genus of K. Rasmussen gave a combinatorial proof of the Milnor conjecture which is proved by using Gauge Theory [48, 50]. We recall the Khovanov homology over Q and the readers are referred to [7, 32, 33, 39, 74, 77, 84].

Let D be a diagram of an oriented link L with crossings 1,2,,n. A state α{0,1}n is obtained by resolving each crossing of D where the ith element denotes the revolution of the crossing i in α. Regard every state as a vertex. Two vertices α and α are adjacent if and only if they differ in exactly one place. Set α=l1lk10lk+1ln, α=l1lk11lk+1ln. Then ξ=l1lk1lk+1ln:αα. We associate each cycle to a graded vector space V=1,x where deg(1)=1,deg(x)=0. There is a vector space Vα for each α such that

Vα=Vlα{rα+n+2n}.

Here, n+ and n are the number of positive crossings and negative crossings in D, respectively. rα is the number of 1's and lα is the number of cycles in α. Let

Ci,=α{0,1}n,rα=i+nVα,

where i=n,,n+. Let m:VVV where

11=1,1x=x1=x,xx=0,

and let △:VVV such that

(1)=1x+x1,(x)=xx.

Define the differential

di,:Ci,(D)Ci+1,(D),

where vVαCi,,

di,(v)=Tail(ξ)=αsign(ξ)dξ(v).

Here, sign(ξ) is determined by the parity of the number of 1's before in ξ. dξ(v) is determined by either m or on the cycles appearing in the changing disk. dξ(v) is the identity on cycles not entering the changing disk.

Definition 2 [33] The Khovanov homology (or cohomology) of an orientable link L is the homology of a bi-graded chain complex (Ci,,di,)

Khi,j(L)=kerdi+1,jimdi,j,

where Ci, and di, are given above for i,jZ.

Definition 3 [34, 45] If its nontrivial homology groups lie on two adjacent diagonals, then the link L is Khovanov homologically thin (or H-thin). If Khovanov homology is completely determined by its Jones polynomial and its signature σ, then L is Khovanov holomogically σ-thin.

3 Alternating links

The alternating links give a classical class of links. They play an important role in Knot Theory. In this section, we review some classical results on the alternating links. Some related computations are referred to [17, 25, 27, 30, 38, 47, 52, 53, 61, 85].

Definition 4 [70] Let D be a diagram. If one passes the over-crossings and under-crossings alternately while moving along each component of D, then D is an alternating diagram. If a link has an alternating diagram, then it is alternating.

The research on alternating links can be traced back to the work of Tait and others in the end of the 19th century. Tait proposed an important conjecture about alternating knots in 1898.

Conjecture 1 [70] A connected reduced alternating diagram has minimal crossing number for the knot.

Kauffman, Murasugi and Thistlethwaite obtained the following results and then independently proved Tait's conjecture.

Theorem 2 [31, 54]  The number of crossings in a connected reduced alternating diagram of L is a topological invariant for a link L.

Theorem 3 [54]  Two connected reduced alternating diagrams of an alternating link have the same number of crossings.

Theorem 4 [72]  If a link L has a connected reduced alternating diagram of n crossings, then:

1) the breadth of VL(t) is exactly n;

2) VL(t) is an alternating polynomial;

3) the coefficients of the terms of VL(t) of maximal and minimal degree are both ±1;

4) if L is prime, and is not a (2,k) torus link, then VL(t) is gapless.

Wu obtained the following result by analyzing the black and white regions in the shaded shadow of a link diagram.

Theorem 5 [26]  Let D be a connected reduced diagram with n crossings. α is its state. If there exists a region R satisfying the following conditions:

1) R and each adjacent region have precisely one common edge;

2) both the black mark and white mark occur on the boundary of R in the coloring of the shadow,

then

l(α)+l(α^)n,

where the revolution of each crossing in α^ is different from that in α.

This deduces the following result.

Corollary 1  A prime connected reduced alternating diagram of a link L is a diagram with the minimum crossings of L.

In the topic of the Khovanov homology of an alternating link, Khovanov obtained the Khovanov homology of T(2,k) over Z as follows [33].

Theorem 6  The Khovanov homology of torus links T(2,k) for k2 are given by

Khi,j(T2,k){Z,ifi=0,j=korj=2k;Z,ifi=2l1,j=4l2k,1lk12,lZ;Z2,ifi=2l,j=4lk,1lk12,lZ;Z,ifi=2l,j=4lk+2,1lk12,lZ;Z,ifi=k,j=3korj=23k,kiseven;0,otherwise.

Bar-Natan computed the Khovanov homology over of all prime knots with crossings up to 11 [7, 8]. Bar-Natan, Garoufalidis and Khovanov proposed the following conjectures based on computations.

Conjecture 2 [7] For any prime alternating knot L there exists an even integer σ and a polynomial Kh(L) in t±1 and q±1 with only non-negative coefficients such that

KhQ(L)=qσ1(1+q2+(1+tq4)Kh(L));

KhZ2(L)=qσ1(1+q2)(1+(1+tq2)Kh(L)).

Here, KhF(L) is the graded Poincaré polynomial of the complex C(L) in the variable t over F, σ is the signature of L and Kh(L) contains only power of tq2.

Conjecture 3 [18] The following result holds for each alternating knot L.

KhQ(t,1)=1+VL(it12)(it12)σ

where i=1, σ is the signature of L.

Conjecture 4 [7, 18] For each alternating knots L, the support of the Khovanov homology lies in the lines

deg(q)=2deg(t)+σ±1.

Lee obtained that the Khovanov homology of an alternating knot was determined by its Jones polynomial and signature and then proved Conjectures 2−4 over Q.

Theorem 7 [39]  For any oriented connected alternating link L, the support of Kh(t,q) lies in

deg(q)=2deg(t)+σ±1

and for some pm with ap=bm=1,

KhQ(t,q)=i=pm(aitiq2iσ(L)1+bitiq2iσ(L)+1).

Theorem 8 [39]  Let L be an oriented connected alternating link with n components S1,S2,,Sn. Then

KhQ(t,q)=qσ(L){(q1+q)(E{2,,n}(tq2)jE,kE2ljk)+(q1+tq2q)Kh(tq2)}

where n2, ljk is the linking number of Sj and Sk.

4 Quasi-alternating links

Ozsváth and Szabó introduced a quasi-alternating link [56]. The unknot and an alternating link are quasi-alternating links, which shows that a quasi-alternating link is a generalization of an alternating link. In this section we recall some results related to the Jones polynomial, the Khovanov homology and differentiation of quasi-alternating links.

Definition 5 The set Q of quasi-alternating links is the smallest set of links which satisfies the following properties:

• the unknot is in Q;

• the set Q is closed under the following operation. Let L be any link which has a diagram with a crossing satisfying the following properties:

1. both resolutions L0,L1Q;

2. det(L)=det(L0)+det(L1).

Then LQ.

Manolescu and Ozsváth proved the following result [45].

Theorem 9  Each quasi-alternating link is Khovanov-thin over Z.

Manolescu [44], Baldwin [3], Greene [21], Champanerkar and Kofman [10] obtained quasi-alternating knots up to 10 crossings. Champanerkar and Kofman [10] proved the result as follows.

Theorem 10  If D1 and D2 are any quasi-alternating knot diagrams, then D1D2 is quasi-alternating.

Some infinite families of links are considered later. According to Conway representation, each rational tangle Tα/β associates a continued fraction such that

aβ=am+1am1+11a2+1a1

where m1, 0<|β|<α, ai0 for 1im. Let u be a crossing of a link diagram D. If we replace u by Tα/β of sign(c)ai1 for 1im, then Tα/β extends u. If each rational tangle in a product extends u, then the product of rational tangles extends the crossing u. Each Montesinos link M(β1α1,β2α2,βnαn,e) has a diagram which consists of m rational tangle Tαi/βi and e half-twists for m1 and 1im. Here, αiβi associate (c1,ic2,icmi,i) for 1im [1, 16]. Then there are the following results.

Theorem 11 [21]  The pretzel link P(p1,,pn,q1,,qm;e)=M((p1,1),,(pn,1),(q1,1),,(qm,1),e) for e,n,m0, pi2, qj3 is quasi-alternating if and only if

(1) e>m1;

(2) e=m1>0;

(3) e=0,n=1, and p1>min{q1,,qm} or m1;

(4) e=0,m=1, and q1>min{p1,,pn} or n1.

The result holds on permuting on the parameters pi and qj.

Theorem 12 [10]  Set D to be a quasi-alternating diagram at some crossing u. Let D be the diagram obtained from D by a rational tangle extending u. Then D is quasi-alternating.

Theorem 13 [10]  The pretzel link P(p1,,pn,q) is quasi-alternating for n1, 1in, each pi1 and q>min(p1,,pn). The conclusion hold for all permutations of pis and qs and for reflections of all these pretzel links.

Theorem 14 [60]  Set D to be a quasi-alternating diagram at some crossing u. Let D be the diagram obtained from D by a product of rational tangles that extends u. Then D is quasi-alternating.

Theorem 15 [60]  The Montesinos link M(β1α1,β2α2,βnαn,e) is quasi-alternating if it satisfies one of the following conditions:

(1) e0;

(2) en;

(3) e=1 for some 1in, αiαiβi>min{αjβj|ji};

(4) e=r1 for some 1in, αiβi>min{αjαjβj|ji}.

These conclusions contain the results related to quasi-alternating Montesinos links [80]. In addition, Chbili and Qazaqzeh considered the Jones polynomial of a quasi-alternating link and then obtained the following result [15].

Theorem 16  Let L be a quasi-alternating link whose diagram D is quasi-alternating at u. Let D be a diagram obtained from D by replacing u by a product of rational tangles extending u. If VL(t) is gapless, then VL(t) is gapless where D is a diagram of L.

Chbili and Kaur considered the diagram from a quasi-alternating diagram by replacing the crossing u by a reduced alternating tangle that extends u. They obtained the conclusion as follows.

Theorem 17  Set D to be a quasi-alternating link diagram at a crossing u. Let D be the diagram obtained from D by replacing u by a reduced alternating tangle T extending u. Then D is quasi-alternating at every crossing of T.

5 Long pass links

A long pass link is introduced in this section. It is different from the notation of the quasi-alternating link. Related problems are provided.

Definition 6 [78] Let D be a link diagram. Assign a letter to each crossing and denote two adjacent crossings a and b by an unordered pair (ar,bs). Then an embedding presentation of D is obtained. Here, r,s{+,}. If (ar,bs) is an overcrossing at a, then ar=a; otherwise r=. Each crossing has an anti-clockwise rotation.

Definition 7 [78] Let P=a0r0a1r1akrkak+1rk+1 be a path in a link diagram D. If k0, a0=ak+1, rj=rj+1{+,} for any 0jk and r0=rk+1, then P is removable. If a0ak+1, k1, rj=rj+1 for each 1jk1, then P=a0r0a1r1akrkak+1rk+1 is a pass of length k. If there doesn’t exist a pass P1 of l(l>k) such that a1r1akrkP1, then P is maximal.

If a diagram D has a removable pass, then it is equivalent to a diagram without any removable pass. Now consider the related operations.

Definition 8 [78] Let D be a link diagram and let ei=(airi,bisi) be edges for i=1,2. If b1s1=a2r2, then e=(a1r1,b2s2) is the union of e1 and e2. Accordingly, e1 and e2 are obtained from e by adding a vertex b1 on e. e1 and e2 is a subdivision of e.

The union implies to remove a crossing b1. The subdivision implies to add a crossing b1. Next consider the operations on passes.

Definition 9 [78] Set D1 to be a link diagram. Suppose that P1=a0ra1ϵa2ϵakϵak+1s is a pass of length k (k1), and ajϵ is adjacent to xjrj,yjsj, (ajϵ,aj+1ϵ) is on the boundary of the face fj for each 1jk where r,ϵ,s,rj,sj{+,}. Remove the pass P1, that is to remove aj and to add (xjrj,yjsj) for each 1jk. Then a figure denoted by D1P1 is obtained. Denote the face containing fj of D1 by fj in D1P1. Add a pass P, that is to add a crossing bi on ei (l1, 1il) in D1P1 such that P=a0r0b1ϵblϵal+1rl+1 is a pass of length l (l1). Then a link diagram D is obtained.

Definition 10 [78] A pass replacement is an operation that one removes a pass D1, adds a pass P and then obtains a link diagram D based on a link diagram D1 where D1,P1,P,D are given above. If k=l and bifi for each 1ik, then P isn't different from P1; otherwise P is different from P1. If l<k, then the replacement is a short pass replacement. If P and P1 are different and l=k, then the replacement is an equal pass replacement. If l>k, then the replacement is a long pass replacement.

The pass replacement is always a replacement between different passes later in the paper.

Definition 11 Let D be a reduced link diagram. If there isn't a short pass replacement in D, then D is a diagram without a short pass. If there is neither a short pass replacement nor an equal pass replacement, then D is a long pass diagram. If a link (or knot) has a long pass diagram, then it is a long pass link (or knot).

An alternating diagram is obvious to be a diagram without a short pass. The non-alternating knot 10152 in the Rolfsen knot table is a long pass knot. Since it is Khovanov holomogically thick [64], it isn't quasi-alternating by Theorem 9. So a diagram without an equal pass is a generalization of an alternating diagram and it is different from the notation of the quasi-alternating diagram. Obviously, the Thistlethwaite's unknot [36] is a diagram without a short pass (Fig.3), which shows that there exists a diagram without a short pass is equivalent to the unknot. Is a long pass link equivalent to the unlink? Several problems are given as follows.

Conjecture 5 Let D be a long pass diagram of a link L with n (n2) crossings. Then D is its diagram with the minimum crossings.

If D is alternating, this conjecture holds. 10152 is a non-alternating link with the minimum crossings satisfying the conjecture.

Problem 1 Characterize the properties of a quasi-alternating and a long pass link, especially diagrams of the unknot.

Problem 2 Study the Jones polynomials of quasi-alternating knots and long pass knots and then study whether the Jones polynomial detects the unknot.

Jones proposed an important conjecture that the Jones polynomial detects the unknot [29]. The conjecture holds for an alternating knot and certain knots and a knot with crossings less than 25. Some results and a detailed introduction are given in [31, 54, 72, 11, 37, 24, 67, 75, 76, 83].

Problem 3 Find an effective method to determine the Khovanov homology of some infinite families of links and study the ability of the Khovanov homology to detect links.

It is hard to determine the Khovanov homology of a link. It can be determined for a link with crossings less than 50 and certain links [65, 12, 20, 40, 43, 51, 49, 58, 59, 66, 68, 73, 69]. It is worth finding methods to determine the Khovanov homology of a general link. The Khovanov homology isn't a complete invariant of a link [79]. Mathematicians have been paying attention to the following important problem:

Find an effective complete invariant of a link, especially a knot.

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