College of Mathematics and Statistics, Hunan Normal University, Changsha 410006, China
xuejunttt@263.net
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Abstract
Let and be a normal function on . In this paper, several equivalent characterizations are given for which composition operators are bounded or compact on the normal weight Dirichlet type space in the unit disc.
Xuejun ZHANG, Min ZHOU, Hongxin CHEN.
Composition operators on the normal weight Dirichlet type space in the unit disc.
Front. Math. China, 2022, 17(4): 545-552 DOI:10.1007/s11464-022-1022-1
Let denote the complex plane, and denote the unit disc in . The class of analytic functions on is denoted by . Suppose that denotes the normalized Lebesgue measure on .
Definition 1.1 A positive continuous function on is called normal if there exist constants and such that is increasing and is decreasing on . For example, ,
, are such normal functions.
For the convenience of proof, let in this paper.
Definition 1.2 Let and be a normal function on . If and
then we say that belongs to the normal weight Dirichlet type space .
In particular, is the Dirichlet type space when . Further, is the Dirichlet space when and .
Definition 1.3 Let be an analytic mapping. Then induces a linear operator on . We say that is a composition operator on .
Composition operators can act on the function space of various support sets to itself or between different function spaces. There have been a lot of references in this field, and many of them involve in composition operator problems on the Dirichlet space or the weighted Dirichlet space (for example, [1-14,16-18,20]). In each case, the main purpose is to find out the relationship between the properties of and the induced symbol . The results closely related to this paper are as follows:
Theorem 1.1 [4, Theorem 3.5] Let be a positive function on the unit interval withsuch that, for each , there is a constantsatisfyingwhenever . For , suppose is the Banach space of all analytic functions on the disc for which the norm given by
If is an automorphism of the unit disc, then is a bounded operator on Y.
Theorem 1.2 [4, p142] For , letbe an analytic mapping. Define the measureonby . Then
(1) is bounded on if and only if ,
(2) is compact on if and only if ().
Theorem 1.3 [10, Theorem 2.5 and Theorem 3.4] For , letsuch thatand . Then
(1) is bounded on if and only if
(2) is compact on if and only if
On the basis of the above results, we give some equivalent characterizations for which composition operators are bounded or compact on for the general normal weight on and all in this paper.
In the following, if there exist constants and such that , then we say that and are equivalent, written as “”. If there exists a constant such that (), then we write “” (“”).
2 Some lemmas
For , let be the involutive automorphism of with and . For and , we define the Bergman disc on , where
For and , let . We know that when . Therefore, we only need to consider the smaller .
This result comes from Proposition 1.4.10 in [15].
Lemma 2.2 [21]There exists a positive integer such that for any we can find a sequencewith the following properties: , and each point belongs to at most of the sets .
Lemma 2.4Letandbe a normal function on . Suppose thatis an analytic self mapping on , and . If is a nonnegative measurable function on , then
where
Ais any Borel measurable set onD.
Proof The condition guarantees that is a finite measure on . This is a general variable substitution formula, which appears in different forms on different occasions. Detailed proof is omitted.
3 Main results and proofs
Theorem 3.1Letandbe a normal function on . Suppose thatis an analytic self mapping on , and . Givenand a finite Borel measure , where
Then the following three conditions are equivalent:
(1) for all and ;
(2) for all ;
(3) is a bounded operator on .
Proof .
Let for all and .
For any , let . When , it follows from Proposition 4.5 in [22] that
This shows that .
Otherwise, recall the definition of normal function and
When , we have . Therefore, we may obtain that
When , we have
This shows that for all .
.
Let for all .
For any , by Lemma 2.20 and Lemma 2.24 in [21], Lemmas 2.2−2.4, we have
This means that is bounded on .
.
Let be bounded on . For any and , we take
When , we have . By the boubdedness of on and Lemmas 2.1 and 2.2, we have
This shows that for all and .
This proof is complete.□
Theorem 3.2Letandbe a normal function on . Suppose thatis an analytic self mapping on , and . Giveand a finite Borel measure , where
Then the following three conditions are equivalent:
(1) ();
(2) ();
(3) is a compact operator on .
Proof .
Let (). For any , let when . It follows Theorem 3.1 that
When , we have . Therefore, we have
.
If (, then for any , there exists a such that
Suppose that is any analytic function sequence which converges to uniformly on any compact subset of and for all . We take the sequence in Lemma 2.2, and we may let . Therefore, there is a positive integer such that when . Let . By (3.1), Lemmas 2.2−2.4, Lemma 2.20 and Lemma 2.24 in [21], we have
By the arbitrariness of , we have . This shows that is a compact operator on .
.
Let be compact on . Let be any sequence tending to zero. For any , we take a function sequence
Then is an analytic function sequence on , which converges to uniformly on any compact subset of and for all and .
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