Existence of solutions to a class of elliptic equations with nonstandard growth condition and zero order term

Zhongqing LI

Front. Math. China ›› 2023, Vol. 18 ›› Issue (1) : 43 -50.

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Front. Math. China ›› 2023, Vol. 18 ›› Issue (1) : 43 -50. DOI: 10.3868/S140-DDD-023-002-X
RESEARCH ARTICLE
RESEARCH ARTICLE

Existence of solutions to a class of elliptic equations with nonstandard growth condition and zero order term

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Abstract

The existence of bounded weak solutions, to a class of nonlinear elliptic equations with variable exponents, is investigated in this article. A uniform a priori L estimate is obtained by the De Giorgi iterative technique. Thanks to the weak convergence method and Minty's trick, the existence result is proved through limit process.

Keywords

Elliptic equations / variable exponents / De Giorgi iteration / Minty's trick

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Zhongqing LI. Existence of solutions to a class of elliptic equations with nonstandard growth condition and zero order term. Front. Math. China, 2023, 18(1): 43-50 DOI:10.3868/S140-DDD-023-002-X

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1 Introduction

Let Ω be a bounded domain of RN with a smooth boundary Ω. We consider the following elliptic equation:

{divA(x,u,u)+g(u)=divF(x),xΩ,u(x)=0,xΩ.

The hypotheses on (1) are given as follows.

(H1): p(x) is a continuous function on Ω¯; and

p+:=maxΩ¯p(x),p:=minΩ¯p(x),

where 1<p<N. Moreover, p(x) satisfies the log-Hölder continuity condition: there exists a constant C>0, such that

|p(x)p(y)|Clog|xy|,

for x,yΩ, |xy|12.

(H2): A(x,s,ξ):Ω×R×RNRN is a vector function which satisfying the Carathéodory condition, i.e., for all (s,ξ)R×RN, A(,s,ξ) is measurable on Ω; for almost all xΩ, A(x,,) is continuous on R×RN. Furthermore, A has the following structure conditions:

[A(x,s,ξ)A(x,s,ξ)](ξξ)0;

A(x,s,ξ)ξα|ξ|p(x);

|A(x,s,ξ)|b(|s|)|ξ|p(x)1,

where α>0; ξ,ξRN. The function b:[0,+)(0,+) is assumed to be continuous.

(H3): F(x) is a vector field; and |F(x)|p(x)Lq(Ω) with q>Np.

(H4): g(s) is a nondecreasing and continuous function on R, and it satisfies

g(s)s0.

The log-Hölder continuity condition (2), stated in (H1), ensures that C0(Ω) is dense in W01,p(x)(Ω) (see the details in [11]).

In order to describe the nonlinear diffusion problem more refined, elliptic and parabolic equations with variable exponents are powerful tools. For more applications in physics, the variable exponent problem is related to the electro-rheological fluids. As pointed out in [15], when subjected to an external electric field, this kind of fluids can give a well description of the ability of a conductor to withstand drastic change of the electric current.

There are numerous papers for this kind of problem like Eq. (1). When the zero order term g=0 and the right-hand side is only L1 integrable in Eq. (1), with the use of the truncation method and monotone operator theory, Bendahmane and Wittbold proved the existence and uniqueness of a class of elliptic p(x)Laplace equation in [2]. For the result concerning parabolic equations, we refer to [3, 17] and the references therein.

In the case of p(x) being a constant and A being a strictly monotone operator, Boccardo and Croce investigated Problem (1) systematically in the monograph [5]. In [4], when g=0, Betta, Guibé and Mercaldo studied the existence and stability of the Neumann boundary problem with a non-coercive term div(c(x)|u|p2u) and an L1 source. A(u)=i=1Nxi(|uxi|pi2uxi) is assumed in [6], the authors considered the case of anisotropic elliptic equation and the corresponding variational problem. The L regularity of this nonstandard growth problem is proved by virtue of Sobolev embedding with anisotropy and the iterative technique. For the maximal norm estimate to the anisotropic parabolic equations, one can refer to [14]. In the framework of Orlicz spaces, a class of elliptic equations, with a principal diffusion term

div[log(1+|u|)|u|u],

is investigated in [9]. With the help of Dunford-Pettis Theorem, the authors obtained the weak convergence in L1 for the gradient solution sequence, as well as the existence of the weak solutions. [10] proved the existence result to a class of parabolic equations in Musielak-Orlicz spaces with discontinuous in time N-function.

When the operator A is strictly monotone, in order to obtain the existence of solution, as in [7], we usually seek the strong convergence or almost everywhere convergence of the gradient sequence {uk}k. However, the operator A in our Problem (1) is only monotone. Compared with the strict monotonicity of operator A, it is not easy to get the strong convergence or almost everywhere convergence of gradient sequence. In essence, it is more complicated to deal with the weak convergence of the nonlinear term.

Theorem 1  If Problem (1) satisfy conditions (H1), (H2), (H3) and (H4), then there exists a bounded weak solution uW01,p(x)(Ω)L(Ω), i.e., for arbitrary ϕW01,p(x)(Ω)L(Ω), there holds

ΩA(x,u,u)ϕdx+Ωg(u)ϕdx=ΩF(x)ϕdx.

2 Proof of Theorem 1

2.1 Regularized problem

Denote

Tk(s)=min{k,max(s,k)},kN;Fk(x)=F(x)1+1k|F(x)|.

Inspired by [4, 9], we construct a regularized equation corresponding to Problem (1):

{1kdiv(|uk|p(x)2uk)divA(x,Tk(uk),uk)+Tk(g(uk))=divFk(x),xΩ,uk(x)=0,xΩ.

Denote

fk=k[divA(x,Tk(uk),uk)Tk(g(uk))divFk(x)],1p(x)+1p(x)=1.

Then fk lies in W1,p(x)(Ω), the duality space of W01,p(x)(Ω).

Based upon the derivation of Section 3.1 and Remark 3.2 in [2], thanks to the monotone operator theory in [16], for every fixed kN, there exists a unique weak solution ukW01,p(x)(Ω) to Eq. (7). Moreover, [6] shows that for every k, uk is in L(Ω) (it is not uniformly bounded in L [7]).

2.2 The result for the case: |F(x)|p(x)L1(Ω)

When the right-hand side term F is endowed with the integrability |F(x)|p(x)L1(Ω), we will prove the necessary a priori estimates for the solution sequence {uk}.

Taking uk as a test function in Problem (7), from (4), (6) and Young inequality abεap(x)+εp(x)p(x)bp(x), we obtain that

Ω1k|uk|p(x)dx+αΩ|uk|p(x)dxΩ1k|uk|p(x)dx+ΩA(x,Tk(uk),uk)ukdx+ΩTk(g(uk))ukdx=ΩFk(x)ukdxα2Ω|uk|p(x)dx+(2α+1)1p1Ω|F(x)|p(x)dx.

Then there holds

Ω1k|uk|p(x)dx+α2Ω|uk|p(x)dx(2α+1)1p1|F(x)|p(x)1,Ω:=C~.

This inequality indicates that {1k|uk|p(x)}k is uniformly bounded in L1(Ω). Simultaneously, {uk}k is uniformly bounded in W01,p(x)(Ω). With the help of (4), we also get

ΩTk(g(uk))ukdx2C~.

The previous estimates imply that there exists a subsequence of {uk}k, still denoted by {uk}k itself, and a uW01,p(x)(Ω), such that for k,

uku,weaklyinW01,p(x)(Ω);uku,weaklyinLp(x)(Ω;RN).

It follows from the Compactness Embedding Theorem in [11] that

uku,stronglyinLp(x)(Ω),a.e.inΩ.

We deduce from (11) and the continuity of g that

Tk(g(uk))g(u),a.e.inΩ,

as k.

Denoted |U| by the Lebesgue measure of the measurable set U. For every ε>0, and for arbitrary measurable subset EΩ and k^R+, there holds

E|Tk(g(uk))|dx=E{xΩ:|uk(x)|k^}|Tk(g(uk))|dx+E{xΩ:|uk(x)|>k^}|Tk(g(uk))|dxE{xΩ:|uk(x)|k^}|g(uk)|dx+1k^E{xΩ:|uk(x)|>k^}|Tk(g(uk))||uk|dx[g(k^)g(k^)]|E|+1k^ΩTk(g(uk))ukdx.

Here, the first term on the right-hand side of (13) is obtained in the following manner: in view of the monotonicity of g and (6),

E{xΩ:|uk(x)|k^}|g(uk)|dx=E{xΩ:|uk(x)|k^}g(uk)sign(uk)dx=E{xΩ:0uk(x)k^}g(uk)dxE{xΩ:k^uk(x)<0}g(uk)dxg(k^)|E|g(k^)|E|.

Noting (9), by choosing k^=k0 sufficiently large, one has

1k0ΩTk(g(uk))ukdx<ε2.

As soon as k^=k0 is fixed in (13), then by selecting δ=ε2[g(k0)g(k0)]+1, when |E|<δ, we see that

E|Tk(g(uk))|dx[g(k0)g(k0)]|E|+1k0ΩTk(g(uk))ukdx<ε2+ε2=ε.

Combining (12) and (14), from the Vitali Theorem [5] we find that

Tk(g(uk))g(u),stronglyinL1(Ω).

2.3 Uniform L-estimate

Under the assumption (H3), when |F(x)|p(x)Lq(Ω), the uniform L estimate of uk will be proved.

Denote Aj={xΩ:|uk(x)|>j}, Gj(s)=(|s|j)+sign(s). Since for every j, Gj(uk)W01,p(x)(Ω)L(Ω), Gj(uk) is able to be employed as a test function to Problem (7). With the use of (4), (6) and Young inequality, we observe that

αΩ|Gj(uk)|p(x)dxΩA(x,Tk(uk),uk)Gj(uk)dxΩFk(x)Gj(uk)dxα2Ω|Gj(uk)|p(x)dx+(2α+1)1p1Aj|F(x)|p(x)dx.

Therefore,

Ω|Gj(uk)|p(x)dx2α(2α+1)1p1Aj|F(x)|p(x)dx.

Moreover,

Ω|Gj(uk)|pdx2α(2α+1)1p1Aj|F(x)|p(x)dx+|Aj|2α(2α+1)1p1|F(x)|p(x)q,Ω|Aj|1q+|Aj|.

Denoted βN,p by the Sobolev constant, (p)=NpNp. By means of Sobolev inequality in [1], we have

Ω|Gj(uk)|pdx1βN,pp(Ω|Gj(uk)|(p)dx)p(p).

Considering the previous two inequalities, one has

Ω|Gj(uk)|(p)dxC1|Aj|1q(p)p+C2|Aj|(p)p,

with C1=2(p)pβN,p(p)[2α(2α+1)1p1](p)p|F(x)|p(x)q,Ω(p)p, C2=2(p)pβN,p(p).

Let h>j. Then |Gj(uk)|hj on the set Ah, we thus arrive at

Ω|Gj(uk)|(p)dx(hj)(p)|Ah|.

In conclusion,

|Ah|C(hj)(p)[|Aj|1q(p)p+|Aj|(p)p],

where C=C1+C2.

Recalling (H3), q>Np1q(p)p>1; and it is obvious that (p)p>1, by virtue of the modified De Giorgi iterative lemma in [13], we actually prove the maximal norm estimate of uk:

supkukL(Ω)C,

where C is independent of k. Furthermore, as k,

uku,weaklyinL(Ω).

From (5) and the uniform L boundedness (16) of uk, we can see that

|A(x,Tk(uk),uk)|maxr[0,supkukL]b(r)|uk|p(x)1.

Moreover, according to (8) and the Nemyckii operator theory with variable exponent in [12], we deduce that A(x,Tk(uk),uk) is uniformly bounded in Lp(x)(Ω;RN); and

A(x,Tk(uk),uk)σ,weaklyinLp(x)(Ω;RN).

2.4 Minty’s trick

Taking advantage of uku as a test function in Problem (7), it results

Ω1k|uk|p(x)dxΩ1k|uk|p(x)2ukudx+ΩA(x,Tk(uk),uk)(uku)dx+ΩTk(g(uk))(uku)dx=ΩFk(x)(uku)dx.

Taking the lim sup on the previous equality, it follows from (10), (15), (17) that both the limits of the forth and the fifth terms are 0. Besides, observe that 1k|uk|p(x)2uk converges weakly to 0 in Lp(x)(Ω;RN). Indeed, for arbitrary φLp(x)(Ω;RN), note the definition of weak convergence, p(x)-Hölder inequality and the relationship between norm and modular in the variable exponent space, by (8) we have

|Ω1k|uk|p(x)2ukφdx|Ω(1k)1p(x)|uk|p(x)1(1k)1p(x)|φ|dx2(1k)1p(x)|uk|p(x)1Lp(x)(Ω)(1k)1p(x)|φ|Lp(x)(Ω)2(Ω1k|uk|p(x)dx+1)1(p)(1k)1p+φLp(x)(Ω)2k1p+(C~+1)1(p)φLp(x)(Ω)0.

Thus the limit of the second integral term is 0. Utilizing (18) we finally get

lim supkΩA(x,Tk(uk),uk)ukdxΩσudx.

For arbitrary ψ(C0(Ω))N, taking into account (5), (11), L boundedness (16) of uk and the Lebesgue Dominated Convergence Theorem, we infer that

A(x,Tk(uk),ψ)A(x,u,ψ),stronglyinLp(x)(Ω;RN),

as k.

In view of the monotonicity (3) of A, together with (10), (18), (19), (20), we deduce that

0lim supkΩ[A(x,Tk(uk),uk)A(x,Tk(uk),ψ)](ukψ)dxlim supkΩA(x,Tk(uk),uk)ukdxΩσψdxΩA(x,u,ψ)(uψ)dxΩ[σA(x,u,ψ)](uψ)dx.

Now selecting ψ=utw with t>0 and w(C0(Ω))N in the previous inequality, then it allows one to get

Ω[σA(x,u,utw)]wdx0.

Letting t0, it follows that

Ω[σA(x,u,u)]wdx0.

Replacing w by w, we conclude that

Ω[σA(x,u,u)]wdx=0,

which gives the required result

σ=A(x,u,u)

by the Minty's trick.

Once (21) is obtained, by using a standard process of passing to the limit, one can prove that u is a bounded weak solution to Problem (1).

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