The high resolution transmission electron microscope pictures supported the above results, i.e., the Cu species entered the Ce(Zr)O
2 lattice at Zr doping≤30%, and the matrix structure was transferred at Zr doping of 50% (Figs. 4(d–e). Both Ce
0.7Cu
0.3O
2 and Ce
0.4Zr
0.3Cu
0.3O
2 showed a lattice distance of ~0.309 nm, which can be assigned to the
d(111) of CeO
2 (0.312 nm, PDF #43-1002). The slight decrease in the
d(111) value suggests that Cu
2+ or Zr
4+ with a smaller ionic radius entered the CeO
2 lattice. Additionally, a lattice distance of ~0.254 nm was also observed for the two samples, which can be assigned to the
d(11-1) of monoclinic CuO (0.252 nm, PDF #48-1548), since CuO crystals are present on the surface. With Ce
0.2Zr
0.5Cu
0.3O
2, the (111) lattice fringe of CeO
2 was not observed, but it appeared with a lattice distance of 0.303 nm, which can be assigned to the
d(101) of the Ce–Zr–O solid solution [
34]. This, in turn, confirms the transformation of the matrix structure from CeO
2 to ZrO
2. As expected, a lattice distance of 0.256 nm (assigned to the
d(11-1) of monoclinic CuO) was observed, due to the re-formation of surface CuO.